泰勒公式问题按x
按x-4的乘幂展开该多项式。请写出详细过程,不胜谢谢
f(x)=x^4-5x^3+x^-3x+4...........f(4)=-56 --->f'(x)=4x^3-15x^+2x-3........f'(4)=21 --->f''(x)=12x^-30x+2...........f''(4)=74 --->f'''(x)=24x-30..............f'''(4)=66 --->f''''(x)=24.................f''''(4)=24 --->f<5>(x)=f<6>(x)=...=0 由Taylor公式: f(x)=f(4)+[f'(4)/1!](x-4)+[f''(4)/2!](x-4)^+      +[f'''(4)/3!](x-4)^3+[f''''(4)/4!](x-4)^4   =-56+21(x-4)+34(x-4)^+11(x-4)^3+(x-4)^4