- 关于比例线段的问题2!如图,已知直线AC、EF、BD分别被直线A
- 如图,已知直线A、EF、BD分别被直线AB、CD所截,AE/EB=CF/FD,依据比例性质证明
(1)AB/EB=CD/FD
(2)AB/CD=AE/CF
- 如图,已知直线AC、EF、BD分别被直线AB、CD所截,AE/EB=CF/FD,依据比例性质证明
(1)AB/EB=CD/FD
已知:AE/EB=CF/FD
所以:(AE/EB)+1=(CF/FD)+1
则,(AE+EB)/EB=(CF+FD)/FD
即:AB/EB=CD/FD
(2)AB/CD=AE/CF
已知AE/EB=CF/FD…………………………………………(1)
又由(1)的结论知道:AB/EB=CD/FD……………………(2)
(1)/(2)得到:
(AE/EB)/(AB/EB)=(CF/FD)/(CD/FD)
即:AE/AB=CF/CD
所以,AB/CD=AE/CF