不等式x+2/(x+1)>2的解集是不等式x+[2/(x+1)]
不等式x+ [2/(x+1)]>2的解集是? 注明：要过程！！
解：x+2/(x+1)＞2 ==> [x(x+1)+2-2(x+1)]/(x+1)＞0 ==> x(x-1)/(x+1)＞0 ==> x(x-1)(x+1)＞0 ==> x∈(-1,0)∪(1,+∞)