高二计算题㈠计算[(1+i)/√2]^2+5i/(3+4i)
㈠计算[(1+i)/√2]^2+5i/(3+4i)
[(1+i)/√2]^2+5i/(3+4i) =（1+i）^2/2+5i(3-4i)/(3+4i)(3-4i) =2i/2+(15i+20)/(9+16) =i+(3/5)i+4/5 =4/5+(8/5)i