积分{lnx/[(1
积分{ lnx/[(1-x)^2]}dx
∫lnx/[(1-x)^2]}dx＝∫lnxd(1/(1-x))＝lnx/(1-x)－∫1/[x(1-x)]dx＝lnx/(1-x)－∫[1/x+1/(1-x)]dx＝lnx/(1-x)－lnx+ln|1－x|+C