问一道英文数学证明题√N+1
√N+1-√N=1/√N+1-√N 这个证明很简单 use this to elain why √101 is close to,but slightly less than,10.05 find the roots of x^2+7x-13=0,giving your answers correct to 2 decimal places.
√101-√100 = 1/(√101+√100）＜ 1/(√100+√100) = 1/20 --->√101 ＜ 10+1/20 = 10.05 x²+7x-13=0 --->x = (-7±√101)/2 = (-7±10.05)/2 ≈ -8.525 or 1.525