概率证明题P73,22证明:当a<=X<=b时,有a
证明:当a<=X<=b时,有a<=EX<=b,0<=DX<=(b-a)^2/4 感谢!
使用这个性质:X≤Y==>E(X)≤E(Y). 1. a≤X≤b==>a=E(a)≤E(X)≤E(b)=b. 2. a≤X≤b==>[X-(a+b)/2]^2≤[(b-a)/2]^2 ==> E[X-(a+b)/2]^2≤E[(b-a)/2]^2=[(b-a)/2]^2 而 E[X-(a+b)/2]^2= =E[X-E(X)+E(X)-(a+b)/2]^2= =E[X-E(X)]^2+2E{[X-E(X),E(X)-(a+b)/2]}+E[E(X)-(a+b)/2]^2=DX+2[E(X)-(a+b)/2]E[X-E(X)]+[E(X)-(a+b)/2]^2 =DX+[E(X)-(a+b)/2]^2 ==> DX+[E(X)-(a+b)/2]^2≤(b-a)^2/4 ==> DX≤(b-a)^2/4