- 高一数学已知(2+cot^2Q)/(1+sinQ)=1,那么(1
- 已知(2+cot^2Q)/(1+sinQ)=1,那么(1+sinQ)(2+
cQ)=( )
- 已知(2+cot^2Q)/(1+sinQ)=1,则:
[2+(cos^Q/sin^Q)]/(1+sinQ)=1
===> (2sin^Q+cos^Q)/(sin^Q+sin^3Q)=1
===> (1+sin^Q)/(sin^Q+sin^3Q)=1
===> 1+sin^Q=sin^Q+sin^3Q
===> sin^3Q=1
===> sinQ=1,且cosQ=0.则:
===> (1+sinQ)(2+coaQ)=(1+1)(2+0)=4