一道数学题急用啊要过程
要过程
解:原式=(a-b)c/abc+a(b-c)/abc-b(c-a)/abc =[(a-b)c+a(b-c)-b(c-a)]/abc =(ac-bc+ab-ac-bc+ab)/abc =(2ab-2bc)/abc =2b*(a-c)/abc =(2a-2c)/ac