已知x∈R,y>0,A={x^2+x+1,

已知x∈R,y>0,A={x^2+x+1,: 已知x∈R,y>0,A={x^2+x+1,-x,-x-1}, B={-y,-y/2,y+1},若A+B,求x^2+y^2的值; 题中可能应该是A=B 如果是这样,那么: x^2+x+1>0,y+1>0,-x-1<-x<0,-y<-y/2<0 由题意:x^2+x+1=y+1,-x-1=-y,-x=-y/2 解得x=1,y=2, x^2+y^2=5.