(sin^A+4)/(cosA+1)=2,(cosA+3)(si?
(sin^A+4)/(cA+1)=2,(cosA+3)(sinA+1)=?
(sin^A+4)/(cosA+1)=2 -->1-cos^A+4=2cosA+2-->cos^A+2cosA-3=0-->(cosA+3)(cosA-1)=0-->cosA=1--->A=2kpai (cosA+3)(sinA+1)=(1+3)(0+1)=4