设f(x)=sin(πx)/3,则f(1)+f(2)+f(3)+?
设f(x)=sin(πx)/3,则f(1)+f(2)+f(3)+…+f(2004)的值为
f(1)=sinπ/3=√3/2 f(2)=sin2π/3=√3/2 f(3)=sinπ=0 f(4)=sin4π/3=-√3/2 f(5)=sin5π/3=-√3/2 f(6)=sin2π=0 f(1)+f(2)+f(3)+f(4)+f(5)+f(6)=0 f(7)=f(1) f(8)=f(2)...... f(x)=f(x+6k) (k为正整数) 则f(1)+f(2)+f(3)+…+f(2004)=0