数学y=f(x)由ln(x+y)=e^（xy）确定，则y'?|x
y=f(x)由ln(x+y)=e^（xy） 确定，则y'?|x=0=
祝新春快乐! ln(x+y)=e^(xy)中, x=0时, lny=e^0=1, y=e; 对隐函数ln(x+y)=e^(xy)求导, (1+y')/(x+y)=e^(xy)*(y+xy') 当x=0, y=e时, (1+y')/e=e y'=e^2-1 即x=0时, y'=e^2-1