- 数学函数已知函数f(x)=Asin(wx+y),x属于R(其中A
- 已知f(x)=Asin(wx+y),x属于R(其中A大于0,w大于0,y属于(0,π/2)周期为π,且图象上一个最低点位M(2π/3,-2)。(1)、求f(x)的解析式。(2)、当x属于(0,π/12),求f(x)的最值
- 注意M是最低点 则:A=2 2π/w = π 所以w = 2;
2π/3 *2 + y = 3π/2+ 2kπ y = 2kπ +π /6
又 y∈(0,π/2) 所以 y =π /6
(1) f(x) = 2sin(2x+ π /6)
(2) x ∈(0,π/12)时, 2x+π/6 ∈(π/6, π/3);
f(x)的最小值为f(π/6) = 1;
f(x)的最大值为f(π/3) = √3;