- 初一数学题急!(1
- (1-1/2-1/3-...-1/2003)*(1/2+1/3+1/4+...+1/2004)-(1-1/2-1/3-...-1/2004)*(1/2+1/3+1/4+...+1/2003)
=?
大家帮忙,要有过程
- (1-1/2-1/3-...-1/2003)*(1/2+1/3+1/4+...+1/2004)-(1-1/2-1/3-...-1/2004)*(1/2+1/3+1/4+...+1/2003)
=?
设:1/2+1/3+1/4+...+1/2003=x
原式=(1-x)(x+1/2004)-(1-x-1/2004)x
=(1-x)x+(1-x)/2004-(1-x)x+x/2004
=1/2004