初一数学题急!(1
(1-1/2-1/3-...-1/2003)*(1/2+1/3+1/4+...+1/2004)-(1-1/2-1/3-...-1/2004)*(1/2+1/3+1/4+...+1/2003) =? 大家帮忙,要有过程
(1-1/2-1/3-...-1/2003)*(1/2+1/3+1/4+...+1/2004)-(1-1/2-1/3-...-1/2004)*(1/2+1/3+1/4+...+1/2003) =? 设:1/2+1/3+1/4+...+1/2003=x 原式=(1-x)(x+1/2004)-(1-x-1/2004)x =(1-x)x+(1-x)/2004-(1-x)x+x/2004 =1/2004