数学计算化简：√[x+2√（x
化简：√[x+2√（x-1）]+√[x-2√（x-1）](x≥1)
根[x+2根(x-1)]=根[(x-1)+2根(x-1)+1]=根[根(x-1)+1]^2=|根(x-1)+1|;同理,根[x-2根(x-1)]=|根(x-1)-1|.考虑到:根(x-1)+1>0,故原式=根(x-1)+1+|根(x-1)-1|.故(1)x-1>=0且根(x-1)-1<0,即1==2时,原式=2根(x-1)