数学解方程组x^2
x^2-y^2=1 { (x-y)^2-2(x-y)-3=0
∵(x-y)^2-2(x-y)-3=0 ∴[(x-y)-3,(x-y)+1]=0 (x-y)=3,(x-y)=-1 ∴x^2-y^2=1 (x-y)(x+y)=1 ∴当(x-y)=3,(x+y)=1/3;x=5/3,y=-4/3 当(x-y)=-1,(x+y)=-1;x=-1,y=0.