求函数值域函数y=1/2(sin2x+sin^2x),x∈R的值
y=1/2(sin2x+sin^2x),x∈R的值域是
2y=sin2x+sin^2x=sin2x+1/2-cos2x/2 2y-1/2=sin2x-cos2x/2=√5/2sin(2x+θ) -√5/2≤2y-1/2≤√5/2 1/4-√5/4≤y≤√5/4+1/4