初二数学若a=1/bc,求a/(ab+a+1)+b/(bc+b+
若a=1/bc,求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1)的值？
已知a=1/bc，所以：abc=1 a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1) =[ac/(abc+ac+c)]+[b/(bc+b+abc)]+[c/(ac+c+1)] =[ac/(1+ac+c)]+[1/(c+1+ac)]+[c/(ac+c+1)] =(ac+1+c)/(1+ac+c) =1.