- 解方程7除以X的2次方+X+1除以X的2次方-X=6除以X的2次
- 7除以X的2次方+X
+
1除以X的2次方-X
=
6除以X的2次方-1
- 7除以X的2次方+X
+
1除以X的2次方-X
=
6除以X的2次方-1
不知道理解错了没!等式如下:
[7/(x^2+x)]+[1/(x^2-x)]=[6/(x^2-1)]
===> [7/x(x+1)]+[1/x(x-1)]=[6/(x+1)(x-1)]
===> [7(x-1)/x(x+1)(x-1)]+[(x+1)/x(x+1)(x-1)]=[6x/x(x+1)(x-1)](通分,公分母为:x(x+1)(x-1))
===> 7(x-1)+(x+1)=6x(方程两边同乘以上述公分母)
===> 7x-7+x+1=6x
===> 8x-6=6x
===> 2x=6
===> x=3
经检验,x=3是原方程的解。(左右两边均等于3/4)