- 三角函数(1
- (1-sinx)/cx=tan(x/2)? 是怎么换算过来的,麻烦给下具体的公式和步骤,谢谢
- 你写的公式不对!,正确的应是
tan(x/2)=(1-cosx)/sinx或tan(x/2)=sinx/(1+cosx)
证明:tan(x/2)=(sinx/2)/(cosx/2))=
[2(sinx/2)(cosx/2)]/[2(cosx/2)(cosx/2)]=
(sinx)/[2(cosx/2)(cosx/2)-1+1]=
(sinx)/(cosx+1)=
(sinx)/(1+cosx)
(sinx)/(1+cosx)
(sinx)(1-cosx)/(1+cosx)(1-cosx)=
(sinx)(1-cosx)/(1-cos^x)=
(sinx)(1-cosx)/(sin^x)=
(1-cosx)/(sinx)
(^表平方)